Download and uncompress gzip at once

Question
1

val myGZIP = scala.io.Source.fromURL(...)

returns scala.io.BufferedSource referring to a gzip file. I would like to use it subsequently in

val gz = new GZIPInputStream(fis)

to be able to process the file

Source.fromInputStream(gz) .

GZIPInputStream requires java.io.InputStream whereas scala.io.Source.fromURL returns scala.io.BufferedSource. Is there any way to convert and chain reading from URL and decoding gzip format?

2

Well, you don’t need Source.fromURL at all.

Just check at its implementation, all you need is: url.openStream()

2 Likes
3

Great, everything works perfectly! Thanks a lot for a prompt response.

4

The fromFoo API in Source is very confusing to me (and I’m not a user). I suspect it could be simplified. In particular, I think you are not wrong in wanting your use case without dipping back into the Java API.

I don’t know what the “correct” or “best” API would be.

I’m glad there is a workaround.