Def Macros: How to get the original tree of an argument passed to a macro (from before type inference)?

The syntax tree of an argument passed to my macro is altered by type inference: notice below that the tree received by identityMacro is Foo.apply[Int](), even though the tree that appears in the source code is just Foo().

How could I get back the original tree?

(I don’t even mind the expansion of Foo() to Foo.apply(), but I don’t want any inferred type arguments to be added.)

Note: c.untypecheck only erases the type, but doesn’t remove the inferred type arguments from the tree.

Thanks for your help,
Tomas

$ scala-2.12.2/bin/scala
Welcome to Scala 2.12.2 (Java HotSpot(TM) 64-Bit Server VM, Java 1.8.0_102).
Type in expressions for evaluation. Or try :help.

scala> :silent

scala> :paste
// Entering paste mode (ctrl-D to finish)

import scala.reflect.macros.whitebox.Context
import scala.language.experimental.macros

def identityMacro(c: Context)(arg: c.Tree): c.Tree = {
  c.echo(arg.pos, s"Tree passed to identityMacro: ${arg}")
  arg
}

def id[A](arg: A): A = macro identityMacro

case class Foo[A]()

// Exiting paste mode, now interpreting.

scala> id[Foo[Int]](Foo())
<console>:17: Tree passed to identityMacro: Foo.apply[Int]()
       id[Foo[Int]](Foo())
                       ^

scala>

This functionality is currently not supported by Scala macros.