How to next in for loop

Question
6

@cbley many thanks for your suggestions.

from my test with your code, it got improvement, but not much.
please see below:

$ scalac -Xscript Hackwords words-parse3.scala 
$ time scala Hackwords > words3.txt

real	0m29.338s
user	0m17.411s
sys	0m13.278s

$ cat words-parse3.scala 
import scala.io.Source
import scala.io.Codec
import java.nio.charset.CodingErrorAction

implicit val codec = Codec("UTF-8")
codec.onMalformedInput(CodingErrorAction.REPLACE)
codec.onUnmappableCharacter(CodingErrorAction.REPLACE)

val patt1 = """[^0-9a-zA-Z\s].*""".r
val patt2 = """[a-z0-9]+""".r
val ws = """\s+""".r

val lines = Source.fromFile("msg.txt").getLines()

for {
  line <- lines
  if ! patt1.matches(line)
  word <- ws.split(line)
  if patt2.matches(word.toLowerCase) && word.size < 30
} {
  println(word)
}

any further suggestion?

Thanks!