Ironically, the specific example `1.0 to 10.0 by 0.01`

was a motivating example for deprecation. For example because `(0.0 to 10.0 by 0.01).toList.last != (0.0 to 10.0 by 0.01).last`

# Deprecated range syntax

**som-snytt**#7

I hope it’s obvious that it should work like the Range.Double example.

I’m returning to the angry Java programmer thread now.

**curoli**#8

What would that simple benign use case be?

If you repeatedly add 0.01 to 1.0, Double will most likely not arrive at 10.0, but at something like 9.99999999999995 or 10.000000000007.

**Russ**#9

That’s why I’m wondering if there was a legitimate technical reason for this deprecation, namely the failure of Doubles to represent some decimal numbers precisely. If I were using this construct in critical code, I would add a small epsilon to the end point to make sure it is not missed due to numerical roundoff. For example:

for (x <- 0.0 to 10.01 by 0.2)

Does BigDecimal makes that little trick unnecessary? (Easy enough to test, but I don’t feel like doing it right now.)

**curoli**#10

If you want a series of equidistant Doubles, use Int indices and calculate, e.g.

__scala> val (min, max, step) = (1.0d, 10.0d, 0.01d)

min: Double = 1.0

max: Double = 10.0

step: Double = 0.01

val n = ((max - min)/step).toInt

n: Int = 900

val doubles = (0 to n).map(i => ((n - i)

min + imax)/n)

doubles: scala.collection.immutable.IndexedSeq[Double] = Vector(1.0, 1.01, 1.02, 1.03, 1.04, 1.05, 1.06, 1.07, 1.08, 1.09, 1.1, 1.11, 1.12, 1.13, 1.14, 1.15, 1.16, 1.17, 1.18, 1.19, 1.2, 1.21, 1.22, 1.23, 1.24, 1.25, 1.26, 1.27, 1.28, 1.29, 1.3, 1.31, 1.32, 1.33, 1.34, 1.35, 1.36, 1.37, 1.38, 1.39, 1.4, 1.41, 1.42, 1.43, 1.44, 1.45, 1.46, 1.47, 1.48, 1.49, 1.5, 1.51, 1.52, 1.53, 1.54, 1.55, 1.56, 1.57, 1.58, 1.59, 1.6, 1.61, 1.62, 1.63, 1.64, 1.65, 1.66, 1.67, 1.68, 1.69, 1.7, 1.71, 1.72, 1.73, 1.74, 1.75, 1.76, 1.77, 1.78, 1.79, 1.8, 1.81, 1.82, 1.83, 1.84, 1.85, 1.86, 1.87, 1.88, 1.89, 1.9, 1.91, 1.92, 1.93, 1.94, 1.95, 1.96, 1.97, 1.98, 1.99, 2.0, 2.01, 2.02, 2.03, 2.04, 2.05, 2.06, 2.07, 2.08, 2.09, 2.1, 2.11, 2.12, 2.13, 2.14, 2.15, 2.16, 2.17, 2.18, 2.19,…

doubles.last

res0: Double = 10.0__

Best, Oliver

**Ichoran**#11

The technical reason that floating-point ranges are deprecated is that precise addition of `Double`

and `Float`

is not guaranteed. In particular, it fails on addition of numbers with a decimal fraction, even if that fraction is “not tiny”, like `0.1`

. The library should not contain methods that mysteriously give you unreliable behavior, hence the deprecation.

The BigDecimal approach solves the issue because the math is performed without imprecision.

There’s no advantage to trying epsilon-shifting schemes because then you may as well just use integers to represent your decimal fraction, for example in the manner that Oliver demonstrated.

One could envision a macro that did the right thing for literals.

**som-snytt**#13

One can dispute whether Range.Double is useful, stepping with precision but delivering doubles, or whether there is another useful sense for double-stepping that could be controlled by a context, but please acknowledge that I am discussing the former, which is limited but by itself is unproblematic. Sometimes all you need or want is an unproblematic solution to an unproblematic problem.

I came back from the angry Java thread even angrier. You wouldn’t like me when I’m angry.

**Russ**#14

It is fairly easy to write a routine that works right by using multiplication and division rather than addition. In fact, I did exactly that a long time ago for my scalar class (which represents physical scalars with units). Here it is:

def scalarSteps(start: Scalar, end: Scalar, step: Scalar): Vector[Scalar] = {

```
val inc = abs(step)
val sgn = Real(signum(step)) // convert to "Double"
val start1 = Real(start/inc)
val end1 = Real(end/inc) + 1e-10 * sgn
(BigDecimal(start1) to end1 by sgn)
.map(_.toDouble).map(_ * inc).toVector
}
```

A simpler version of this (replace Scalar with Double) could be provided by default for so-called “Doubles” in Scala so that the deprecated syntax could be maintained and would work correctly. That would relieve users of spending time to figure out how to use BigDecimal. It would also result in a tiny performance penalty, but I would gladly take the slight hit in return for the convenience.

**Russ**#15

For what it’s worth, It just occurred to me that if the human race had chosen base 8 (octal) instead of base 10 as the standard numeral system, we wouldn’t have this problem. People say we use base 10 because we have ten fingers, but actually we have 8 fingers and two thumbs! Too late to fix that one, I guess!

**Ichoran**#18

Binary-coded integers can represent whole decimal numbers exactly. Binary fractions, which is what Float and Double are, cannot represent decimal fractions exactly. So `1 to 7 by 2`

is calculated without error.

**curoli**#19

I’m sorry, but I truly do not see why you think Range.Double is “unproblematic”. What do you think about this behavior:

**Welcome to Scala 2.12.4 (OpenJDK 64-Bit Server VM, Java 1.8.0_171).

Type in expressions for evaluation. Or try :help.

Range.Double(0.0, 7.0, 1.0).last

res0: Double = 6.0

Range.Double(0.0, 0.7, 0.1).last

res1: Double = 0.7000000000000001**

Best, Oliver

**Ichoran**#20

Even if you step with precision you run into surprises. What should the behavior of `0.1 until 3*0.1 by 0.1`

be? More sneakily, suppose you have `def steps(x: Double) = x until 3*x by x`

. Shall this sometimes give you three elements and sometimes two?

The imprecision can easily arrive *in the input* which is why a solution with precise stepping isn’t really a solution.

**som-snytt**#21

That’s just a bug. The code comment is:

`// XXX This may be incomplete.`

And with the appropriate override,

```
scala> Range.Double(0, .7, .1).last
<console>:12: warning: method apply in object Double is deprecated (since 2.12.6): use Range.BigDecimal instead
Range.Double(0, .7, .1).last
^
res1: Double = 0.6
```

**som-snytt**#22

I still insist that in the age of literal types and macros, it’s not too much magic to insist on literals or at least take warning action. `0 to .7 by .1`

, give me `BD`

s or `Double`

s or whatever seems to be expected.

Or at least enable a Propensive library to do it for me.

**Russ**#23

That doesn’t work right on 0.1 to 0.299999999999 by 0.2.

But it’s “close enough for government work,” as they say!

I actually use something like this to discretize a bounding area for a numerical algorithm, and I definitely need to capture the end point. But I need to capture the end point even if it is in the middle of a step, which is a slightly different problem. I could just add the end point to the end of the sequence, but then I would usually be repeating the end point. So I came up with this little scheme:

def scalarStepsx(start: Scalar, end: Scalar, step: Scalar): Vector[Scalar] = {

// same as scalarSteps except guaranteed to include end point

```
val steps = scalarSteps(start, end, step)
if (areClose(steps.last, end)) steps else steps :+ end
}
```

def areClose(x: Scalar, y: Scalar) =

if (y == 0) x == 0 else abs(x / y - 1) < 1e-13

**Ichoran**#24

That one also has counterexamples where it does the wrong thing (e.g. `0.1 to 0.300000000001 by 0.1`

). None of these are suitable for a library method that should act “intuitively”.

**Ichoran**#25

@som-snytt - I don’t have any objection to a working macro. I’m not likely to be able to write one in a reasonable amount of time myself, though.

As Russ’s examples indicate, it’s tricky to get it working. The only really safe thing to do is pass literal numeric arguments into the BigDecimal string constructor, picking them directly out of the text of the code (not the Double literal computed by the compiler).