Say I have:
val a: Future[A]
val b: Future[B]
And I want to combine them into:
val y: Future[(Try[A], Try[B])]
How can I do that?
There is a method zip on Future, but that gives Future[(A, B)], i.e. it fails if either a or b fails, thus potentially losing information.
You may use transform to lift the hidden error channel of the Future into an explicit one, and then zip them like this:
val y = a.transform(t => Success(t)) zip b.transform(t => Success(t))
Thanks. It’s odd that this is not in the stdlib though. Same with Future.sequence.